50 Physics Objective Questions on Quantities, Units, Measurements & Dimensions (With Answers and Solutions)
50 Physics Objective Questions on Quantities, Units, Measurements & Dimensions (With Answers and Solutions)
This set of 50 objective questions covers the core physics topics of quantities, units, measurements, and dimensions. It is designed for students preparing for JAMB, WAEC, and NABTEB examinations, as well as for educators looking for practice resources. Questions range from identifying fundamental and derived quantities, deriving SI units, performing dimensional analysis, to understanding measuring instruments and measurement errors. Detailed solutions are provided for calculation-based questions to enhance understanding.
50 JAMB, WAEC & NABTEB Biology Questions on The Mammalian Ear (Theory and Objective) With Answers
Questions
- Which of the following is a fundamental quantity?A. Area
B. Volume
C. Time
D. Density
- The SI unit of luminous intensity is theA. Kelvin
B. Mole
C. Candela
D. Ampere
- Which of the following is NOT a fundamental quantity?A. Mass
B. Electric current
C. Temperature
D. Force
- The SI unit of amount of substance is theA. kilogram
B. mole
C. candela
D. ampere
- Which pair correctly matches a fundamental quantity with its SI unit?A. Length – kilogram
B. Mass – metre
C. Temperature – Kelvin
D. Time – ampere
- A derived quantity is one thatA. cannot be measured
B. is independent of fundamental quantities
C. is obtained from a combination of fundamental quantities
D. has no SI unit
- Which of the following is a derived quantity?A. Electric current
B. Mass
C. Power
D. Length
- The derived unit of area isA. m
B. m²
C. m³
D. kgm⁻²
- Which of the following quantities has the derived unit kgm⁻³?A. Volume
B. Density
C. Force
D. Pressure
- The derived unit of velocity isA. ms⁻²
B. ms⁻¹
C. kgms⁻¹
D. m²s⁻¹
- Acceleration has the derived unitA. ms⁻¹
B. ms⁻²
C. kgms⁻²
D. ms²
- Using the defining equation force = mass × acceleration, the derived unit of force isA. kgms⁻¹
B. kgms⁻²
C. kgm²s⁻²
D. kgm⁻¹s⁻²
- The SI unit of power, the watt, can be expressed asA. kgms⁻²
B. kgm²s⁻³
C. kgm²s⁻²
D. kgm⁻¹s⁻²
- The derived unit of pressure (Nm⁻²) is equivalent toA. kgms⁻²
B. kgm⁻¹s⁻²
C. kgm²s⁻²
D. kgm⁻²s⁻¹
- Which of the following is dimensionally equivalent to the unit of impulse?A. kgms⁻¹
B. kgms⁻²
C. kgm²s⁻¹
D. Nm
- Dimensions of a physical quantity show how it is made up in terms ofA. SI units
B. fundamental quantities
C. derived quantities
D. measurement instruments
- There are three fundamental dimensions used to describe most physical quantities. They areA. L, M, T
B. M, K, A
C. L, M, K
D. T, L, A
- The dimension of length is represented byA. M
B. L
C. T
D. K
- The dimension of mass isA. L
B. T
C. M
D. A
- Derive the dimensions of velocity.A. LT⁻¹
B. LT⁻²
C. MLT⁻¹
D. ML⁻¹
- The dimensions of acceleration areA. LT⁻¹
B. LT⁻²
C. MLT⁻²
D. L²T⁻¹
- The dimensions of force areA. MLT⁻¹
B. MLT⁻²
C. ML²T⁻²
D. ML⁻¹T⁻²
- The dimensional formula for energy (work) isA. MLT⁻¹
B. ML²T⁻²
C. MLT⁻²
D. ML⁻²T⁻²
- Which of the following has dimensions ML⁻¹T⁻²?A. Force
B. Pressure
C. Momentum
D. Power
- The dimensions of impulse areA. MLT⁻¹
B. MLT⁻²
C. ML²T⁻²
D. ML⁻¹T
- The instrument used to measure length in the laboratory that has an accuracy of 1mm or 0.1cm is theA. micrometer screw gauge
B. vernier calipers
C. metre rule
D. measuring tape
- A metre rule is graduated from 0 toA. 50 cm
B. 100 cm (1 metre)
C. 30 cm
D. 200 cm
- The smallest graduation on a typical metre rule isA. 0.01 cm
B. 0.1 cm (1 mm)
C. 1 cm
D. 0.001 cm
- Error due to parallax in measurement occurs whenA. the instrument has a zero error
B. readings are viewed from a slanting position of the eye
C. the object is too hot
D. the scale is not calibrated
- A length is measured as 51.3 ± 0.1 cm. The value 0.1 cm represents theA. actual length
B. absolute error
C. estimated uncertainty
D. percentage error
- Which measuring instrument is suitable for measuring longer lengths like a road or a piece of land?A. Metre rule
B. Vernier calipers
C. Measuring tape
D. Micrometer screw gauge
- The calipers are used in conjunction with the metre rule to measureA. internal diameter of a test tube
B. thickness of a wire
C. external diameter of cylindrical objects
D. depth of a beaker
- Frequency is defined as the number of cycles per unit time. Its derived unit isA. s
B. s⁻¹ (hertz)
C. ms⁻¹
D. s²
- Which of the following quantities is dimensionless (dimensionally independent)?A. Efficiency
B. Momentum
C. Power
D. Force
- The refractive index of a medium is dimensionless because it is the ratio of theA. speeds of light in two media
B. sines of angles (ratio of lengths)
C. densities of two media
D. wavelengths of light
- Dielectric constant (relative permittivity) is dimensionally independent because it is the ratio ofA. two masses
B. two times
C. two capacitances
D. two lengths
- Which of the following groups contains only derived quantities?A. Mass, time, length
B. Temperature, electric current, luminous intensity
C. Area, volume, density, force
D. Amount of substance, temperature, time
- The SI unit of momentum isA. kgms⁻²
B. kgms⁻¹
C. Ns
D. both B and C
- One joule (J) is equivalent toA. 1 Nm
B. 1 kgm²s⁻²
C. 1 watt-second
D. all of the above
- The product of force and time gives the quantityA. work
B. impulse
C. power
D. pressure
- The dimension of power can be written asA. MLT⁻²
B. ML²T⁻³
C. ML²T⁻²
D. MLT⁻¹
- Which of the following is a fundamental quantity?A. Torque
B. Electric current
C. Momentum
D. Pressure
- The SI unit of temperature isA. Celsius
B. Fahrenheit
C. Kelvin
D. Joule
- In the equation T = 2π√(l/g), T represents period, l length, and g acceleration due to gravity. The dimension of g isA. LT⁻¹
B. LT⁻²
C. L²T⁻¹
D. MLT⁻²
- The period T of a simple pendulum depends on length l and acceleration g. Using dimensional analysis, T is proportional toA. l/g
B. l × g
C. √(l/g)
D. √(g/l)
- An example of a human error in measurement isA. zero error
B. backlash error
C. parallax error
D. calibration error
- If a student reads the scale of a metre rule from an angle instead of directly perpendicular, the error introduced isA. random error
B. parallax error
C. zero error
D. systematic error
- Which of these physical quantities is correctly paired with its SI unit?A. Power – Js⁻¹
B. Specific latent heat – Jkg⁻¹K⁻¹
C. Pressure – Nm⁻¹
D. Density – kgm³
- The derived unit of torque is the same as that ofA. force
B. work (energy)
C. power
D. impulse
- The unit kgm²s⁻² is equivalent toA. watt
B. newton
C. joule
D. pascal
Answer Key
- C
- C
- D
- B
- C
- C
- C
- B
- B
- B
- B
- B
- B
- B
- A
- B
- A
- B
- C
- A
- B
- B
- B
- B
- A
- C
- B
- B
- B
- C
- C
- C
- B
- A
- B
- C
- C
- D
- D
- B
- B
- B
- C
- B
- C
- C
- A
- B
- B
- C
Solutions to Selected Questions
Q12: Force = mass × acceleration. Unit of mass = kg, unit of acceleration = ms⁻². So unit of force = kg × ms⁻² = kgms⁻² (Newton, N). Answer B.
Q13: Power = work/time = force × distance/time = (kgms⁻² × m)/s = kgm²s⁻³. Answer B.
Q14: Pressure = force/area. Unit of force = kgms⁻², area = m². So pressure unit = kgms⁻² / m² = kgm⁻¹s⁻². This is also called the Pascal (Pa). Answer B.
Q15: Impulse = force × time. Unit of force is kgms⁻², multiplied by time (s) gives kgms⁻¹. Also equivalent to Ns. Answer A.
Q20: Velocity = displacement/time. Dimension of displacement = L, time = T. Therefore dimension of velocity = L/T = LT⁻¹. Answer A.
Q22: Force = mass × acceleration. Dimension of mass = M, acceleration = LT⁻². So force = M × LT⁻² = MLT⁻². Answer B.
Q23: Work = force × distance. Dimension of force = MLT⁻², distance = L. Therefore work = MLT⁻² × L = ML²T⁻². Answer B.
Q24: Pressure = force/area = MLT⁻² / L² = ML⁻¹T⁻². Answer B.
Q25: Impulse = force × time = MLT⁻² × T = MLT⁻¹. Answer A.
Q34: Efficiency = (useful work output / total work input) × 100%. The dimensions of work cancel out, so efficiency is dimensionless. Answer A.
Q35: Refractive index n = sin i / sin r. Sine is a ratio of two lengths (opposite/hypotenuse), so the dimensions cancel, making it dimensionless. Answer B.
Q36: Dielectric constant = C_d / C_v (ratio of capacitances), thus dimensionless. Answer C.
Q42: Power = work/time. Dimension of work = ML²T⁻², time = T. Power = ML²T⁻² / T = ML²T⁻³. Answer B.
Q46: T = k lˣ gʸ. Dimensions: T = Lˣ (LT⁻²)ʸ = Lˣ⁺ʸ T⁻²ʸ. Equating powers: for L: x+y=0; for T: -2y=1 => y=-1/2, x=1/2. So T ∝ l^(1/2) g^(-1/2) = √(l/g). Answer C.
Q50: Work (energy) = force × distance = kgms⁻² × m = kgm²s⁻² (joule). Answer C.


